2m^(2/3)+3m^((1/3))-2

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Solution for 2m^(2/3)+3m^((1/3))-2 equation: 


m in (-oo:+oo)

2*m^(2/3)+3*m^(1/3)-2 = 0

t_1 = m^(1/3)

2*t_1^2+3*t_1^1-2 = 0

2*t_1^2+3*t_1-2 = 0

DELTA = 3^2-(-2*2*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)-3)/(2*2) or t_1 = (-25^(1/2)-3)/(2*2)

t_1 = 1/2 or t_1 = -2

t_1 = -2

m^(1/3)+2 = 0

1*m^(1/3) = -2 // : 1

m^(1/3) = -2

( -2 < 0 i 1/3 in (0:1) ) => m naleu017Cy do O

t_1 = 1/2

m^(1/3)-1/2 = 0

1*m^(1/3) = 1/2 // : 1

m^(1/3) = 1/2

m^(1/3) = 1/2 // ^ 3

m = 1/8

m = 1/8

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